[Maxima] variable evaluation
zoho.vignochi at gmail.com
Tue Apr 3 15:54:35 CDT 2007
> solve returns a list like [x = ..., x = ...] to represent multiple solutions;
> that's why a[1, 1] = ... shows up in the value assigned to a[1, 1].
> You could put a[i, i - j] : map(rhs, solve(...)) and likewise for K[i].
> But it seems like a helpful consequence of the present code that
> a[i, j] = ... shows up in the value --- otherwise you would have to
> piece that together from arrayinfo(a) (to get the indices) and
> listarray(a) (to get the values).
Yes, when I run my code with n=2 and then check the output I get
So here is all the information needed to evaluate each of the terms in K
and a. I do not know, and haven't found but searching, a method to
substitute the values into the expressions.
I am looking for
Any help much appreciated!
Thank you for your time,
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