[Maxima] Solving a two equation system yields strange results
Jason Filippou
jason.filippou at gmail.com
Wed May 9 13:46:17 CDT 2012
Good afternoon.
I've been using Maxima 5.21.1 in a Debian GNU / Linux 2.6.32-5-686
system to solve a particular two equation system that I have to. The
system is as follows:
(1): b*(k - 1) = 0.1
(2): exp(-1/b) / sum(i! * b^i, i, 0, k -1) = 0.02
I've been using solve/2 for this, but I've been returned an empty
solution set. Namely:
%i9) solve([b * (k - 1) = 0.1, exp(-1/b) / sum(i! * b^i, i, 0, k -1) =
0.02], [b, k]);
rat: replaced -0.1 by -1/10 = -0.1
rat: replaced -0.02 by -1/50 = -0.02
(%o9) []
Now, normally I would assume that this means that the system doesn't
have a solution, but after substituting beta with its equivalent from
the first equation, i.e 0.1 / (k - 1), I noticed that the evaluation
of the second equation halts after a couple of steps:
(%i5) solve([exp(-(k - 1) / 0.1) * sum(1/(i! * (0.1 / (k-1))^i), i, 0,
k -1) = 0.02], [k]);
rat: replaced -0.02 by -1/50 = -0.02
rat: replaced 0.1 by 1/10 = 0.1
rat: replaced 10.0 by 10/1 = 10.0
%i %pi
------
5
1 - k %e
(%o5) [%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
2 %i %pi
--------
5
1 - k %e
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
3 %i %pi
--------
5
1 - k %e
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
4 %i %pi
--------
5
1 - k %e
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
1 - k 1
%e = - -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
5 k - 4 %i %pi - 5
- ------------------
5 1
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
5 k - 3 %i %pi - 5
- ------------------
5 1
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
5 k - 2 %i %pi - 5
- ------------------
5 1
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
5 k - %i %pi - 5
- ----------------
5 1
%e = -----------------------------------,
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
1 - k 1
%e = -----------------------------------]
k - 1
==== i i
1/10 1/5 \ 10 (k - 1) 1/10
2 5 ( > ------------)
/ i!
====
i = 0
And then if I try to "solve" it any further I get no solutions:
(%i6) solve(%, [k]);
(%o6) []
What am I doing wrong here?
Thanks,
Jason
--
Jason Filippou
Research Associate
NCSR Demokritos
NCSR Webpage: http://users.iit.demokritos.gr/~jfilip/
D.I.T Webpage: http://cgi.di.uoa.gr/~std06142/
LinkedIn! Profile: http://www.linkedin.com/profile/view?id=132927442&trk=tab_pro
--
Jason Filippou
Research Associate
NCSR Demokritos
NCSR Webpage: http://users.iit.demokritos.gr/~jfilip/
D.I.T Webpage: http://cgi.di.uoa.gr/~std06142/
LinkedIn! Profile: http://www.linkedin.com/profile/view?id=132927442&trk=tab_pro
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